OXIDATION AND REDUCTION HALF REACTIONS
Redox reactions involve both an oxidation half reaction and a reduction half
reaction. In electron transfer reactions the electrons come from one compound
(the donor) and are received by another (the acceptor). The electrons are donated
by the oxidation half reaction and accepted by the reduction half reaction. As
shown below, both the donor and acceptor need to be present for the electrons
to transfer.
The electrochemical cell
A good example for illustrating the concept of half reactions is an electrochemical
cell (a simple battery). In an electrochemical cell, chemical redox reactions
drive the movement of electrons through a wire—generating electricity. We
can better understand how this works by examining the half reactions involved.
In a zinc–copper electrochemical cell, when zinc metal is placed in a
zinc sulfate solution it donates electrons, which travel along the metal wire
and are accepted by copper ions in a copper sulfate solution. The loss of electrons
by the zinc metal causes Zn2+ ions to be formed, and the gain of electrons
by the Cu2+ ions results in the formation of copper metal. This electron
flow, or electricity, occurs only when the zinc and copper sources are connected
to one another in a complete circuit. To complete the circuit, the two solutions
are connected by a salt bridge that permits the passage of K+ and Cl
ions. The overall charge of both the zinc and copper baths needs to stay neutral.
As negatively charged electrons leave the zinc bath, they are replaced by Cl
ions that move in from the KCl solution. As positively charged copper ions combine
with incoming electrons to make neutral copper metal, K+ ions move
into the copper bath to replace the lost positively charged Cu2+ ions.
In each vessel of the electochemical cell, individual oxidation or reduction reactions are occuring. These half reactions are separated by a wire that serves to move the electrons and couple both into a redox reaction. Each of these two separated reactions are called the "half reactions," for they each represent half of the total redox reaction: one an oxidation, the other a reduction. The half reactions are shown below.
Zn Zn2+
+ 2 e |
(oxidation half reaction) |
Cu2+ + 2e
Cu |
(reduction half reaction) |
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The half reaction
Redox reactions are very important to living organisms. As an example, for
animals under nonstrenuous conditions, aerobic metabolism reduces O2
to generate ATP to power the muscles. During vigorous exercise when muscles consume
O2 faster than it can be replenished by circulating blood, muscles
can keep working hard by fermenting pyruvate, a byproduct of glucose metabolism.
The overall reaction is
pyruvate + NADH + H+ lactate
+ NAD+ |
|
This redox reaction consists of two half reactions:
pyruvate + 2 H+ + 2 e lactate |
pyruvate gains e |
(reduction half reaction) |
NADH + H+ NAD+
+ 2H+ + 2 e |
NADH loses e |
(oxidation half reaction) |
|
The NAD+ generated is used in other metabolic reactions to generate more ATP. The lactate (lactic acid) produced by this reaction is believed to be responsible for the burn that you feel in muscles that you worked too hard.
Chemistry and biochemistry textbooks list half reactions in tables similar
to the one shown below.
REDUCTION POTENTIALS |
Half Reaction |
E°' (Volts) |
O2 + 2 H+ + 2 e H2O |
0.816 V |
SO42
+ 2 H+ + 2 e SO32
+ H2O |
0.480 V |
fumarate + 2H+ + 2
e succinate |
0.030 V |
acetaldehyde + 2 H+
+ 2 e ethanol |
0.163 V |
oxaloacetate + 2 H+
+ 2 e malate |
0.175 V |
FAD + 2H+ + 2 e FADH2 |
0.180 V |
NAD+ + 2H+
+ 2 e NADH
+ H+ |
0.180 V |
pyruvate + CO2 + 2H+
+ 2 e malate |
0.330 V |
|
Notice how half reactions are always listed as reductions, that is, as gaining
electrons. An oxidation half reaction is simply the reverse of the corresponding
reduction reaction. Notice also that each half reaction is accompanied by its
reduction potential, E°'. The significance of
this value will be examined in the next section.
The reduction half reactions in the table show the compounds gaining electrons,
as you would expect, but also note that these organic reactions are shown as also
gaining protons (H+ ions). Remember that for redox reactions of biological
compounds, hydrogen atoms are often being transferred. For example, recall the
reaction for methane combustion that we encountered in the first section:
CH4 |
+ |
2O2 |
|
CO2 |
+ |
2H2O |
methane |
|
oxygen |
|
carbon
dioxide |
|
water |
|
|
The oxygen atom gained hydrogen atoms and was reduced. Since a hydrogen atom is simply a proton and an electron combined, reduction can be thought of as gaining an electron or as gaining a hydrogen. Another way to think about this is that if a compound gains a hydrogen atom, then it is gaining an electron (reduction) as well as a proton.
Example 3
Using the half reaction table above, split the following biochemical redox reaction into its constituent half reactions. Identify the oxidation half reaction and the reduction half reaction when the redox reaction proceeds as written (from left to right):
succinate + FAD fumarate
+ FADH2
|
Answer:
Looking at the half reaction table, we find two appropriate half reactions:
(1) |
fumarate + 2H+ + 2e succinate |
(2) |
FAD + 2H+ + 2e FADH2 |
We can reverse reaction (1) and add it to reaction (2) to produce the overall reaction:
(1 reversed) |
succinate fumarate
+ 2H+ + 2e |
(2) |
FAD + 2H+ + 2e FADH2 |
|
|
(Sum) |
succinate + FAD fumarate
+ FADH2 |
Reaction (1) is written as losing electrons, and is thus the oxidation half reaction. Reaction (2) is written as gaining electrons, and is thus the reduction half reaction.
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